2h^2+3h-1224=0

Solution for 2h^2+3h-1224=0 equation:

2h^2+3h-1224=0

a = 2; b = 3; c = -1224;
Δ = b2-4ac
Δ = 32-4·2·(-1224)
Δ = 9801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9801}=99$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-99}{2*2}=\frac{-102}{4}
=-25+1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+99}{2*2}=\frac{96}{4}
=24
$